A Given Mass Of Hydrogen Occupies 20.0l At 600 Torr. What Volume Will It Occupy At 1.50atm?
A given mass of hydrogen occupies 20.0L at 600 torr. What volume will it occupy at 1.50atm?
GIVEN:
Volume 1, V1 = 20.0 L
Pressure 1, P1 = 600 torr
V2 = ?
P2 = 1.50 atm = 1140 torr
FORMULA:
(P1)(V1) = (P2)(V2)
EQUATION:
(P1)(V1) = (P2)(V2)
(P1)(V1)/(P2) = V2
SOLUTION:
(P1)(V1)/(P2) = V2
(600 torr)(20.0 L)/(1140 torr) = V2
(12000 torr•L)/(1140 torr) = V2
(1200 torr•L) / (114 torr) = V2
(600 torr•L) / (57 torr) = V2
10.5263157895 L = V2
ANSWER:
The volume is approximately 10.5 L.
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