A Given Mass Of Hydrogen Occupies 20.0l At 600 Torr. What Volume Will It Occupy At 1.50atm?

A given mass of hydrogen occupies 20.0L at 600 torr. What volume will it occupy at 1.50atm?

 

GIVEN:

Volume 1, V1 = 20.0 L

Pressure 1, P1 = 600 torr

V2 = ?

P2 = 1.50 atm = 1140 torr

FORMULA:

(P1)(V1) = (P2)(V2)

EQUATION:

(P1)(V1) = (P2)(V2)

(P1)(V1)/(P2) = V2

SOLUTION:

(P1)(V1)/(P2) = V2

(600 torr)(20.0 L)/(1140 torr) = V2

(12000 torr•L)/(1140 torr) = V2

(1200 torr•L) / (114 torr) = V2

(600 torr•L) / (57 torr) = V2

10.5263157895 L = V2

ANSWER:

The volume is approximately 10.5 L.


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